Copper Sulfate Mole Ratio Lab
Étude de cas : Copper Sulfate Mole Ratio Lab. Recherche parmi 300 000+ dissertationsPar Holytaxidermy • 28 Octobre 2018 • Étude de cas • 1 053 Mots (5 Pages) • 712 Vues
Copper Sulfate Mole Ratio Lab
Analysis
Table 1: Primary data
Substance | Mass (g) ± 0.01g |
Crucible + cover | 22.56 |
Crucible + cover + hydrate | 24.25 |
Crucible + cover + CuSO4 (post first burn) | 23.62 |
Crucible + cover + CuSO4 (post second burn) | 23.61 |
Qualitative observations
Post-burns, the CuSO4 became whiter, as opposed to the blue of the hydrate. The longer it burnt, the more white it appeared. However, the first burn continued for too long, and the CuSO4 began to appear slightly grey.
Table 2: Mass of chemicals
Substance | Mass (g) |
Hydrate | 1.69** ± 0.02* |
CuSO4 (post first burn) | 1.06 ± 0.02 |
CuSO4 (post second burn) | 1.05 ± 0.02 |
H2O lost | 0.64*** ± 0.04 |
*Uncertainties calculated by adding uncertainties of addends (according to Table 1, 2)
Ex: Uncertainty of hydrate = 0.01 + 0.01 = 0.02
**Masses calculated by subtracting mass of crucible + cover from mass of crucible + cover + substance (Table 1)
Ex: Mass of hydrate = (Mass of crucible + cover + hydrate) - (Mass of crucible + cover)
= 24.25 - 22.56 = 1.69
*** Mass of H2O lost = (Mass of hydrate) - (Mass of CuSO4-- post second burn) = 1.69 -
1.05 = 0.64
Table 3: Molar masses and moles of substances
Substance | Molar Mass (g)* | Moles (mol) |
CuSO4 | 159.60(36)** | 0.0065(78799)*** ± 0.0001**** |
H2O | 18.0152 | 0.035(5255562) ± 0.002 |
*According to Sargent-Welch Scientific Company. Calculated by adding masses of constituent parts
Ex: Molar mass of CuSO4 = Mass of Cu + Mass of S + Mass of O * 4 = 63.546 + 32.06 +
15.9994 * 4 = 159.60
**Numbers in brackets are not significant
*** Mols calculated by dividing mass of substance by molar mass of substance (Table 2)
Ex: Moles of CuSO4 = mass of CuSO4 / molar mass of CuSO4 = 1.05 / 159.6036 =
0.00658
****Uncertainty calculated by multiplying decimal uncertainty of mass of substance by moles of substance (Table 2)
Ex: Uncertainty of mols of CuSO4 = (Uncertainty of mass of CuSO4 / Mass of CuSO4) *
moles of CuSO4 = 0.02 / 1.05 * 0.006578799 = 0.0001
Mole ratio
- Divide moles of CuSO4 and H2O by the moles of CuSO4
- CuSO4: 0.0065(78799) / 0.0065(78799) = 1.0 ± 0 mol
- Uncertainty calculated by multiplying sum of decimal uncertainties of moles of CuSO4 to mole ratio = (0.0001 * 2) / 0.006578799 * 1 = 0.03 = effectively zero (Table 2, 3)
- H2O: 0.035(5255562) / 0.0065(78799) = 5.4(00006323) ± 0.4 mol
- Mole ratio: anhydrous saltwater= 1.0 ± 0.05.4 ± 0.04
Evaluation
The goal of the lab was to determine the mole ratio of CuSO4 and H2O. By translating the mass of the substances into moles, I determined that the mole ratio of CuSO4 : H2O was roughly 1:5.4. According to EndMemo Chemistry, the ratio should have been 1:5 (2017). Therefore, the conclusion was relatively accurate. The result was slightly too small, but the moles of H2O is ±0.4, which would make the mole ratio exactly correct.
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